A=(x^2+14x+48)

Solution for A=(x^2+14x+48) equation:

=(A^2+14A+48)

We move all terms to the left:

-((A^2+14A+48))=0


We calculate terms in parentheses: -((A^2+14A+48)), so:

(A^2+14A+48)

We get rid of parentheses

A^2+14A+48

Back to the equation:

-(A^2+14A+48)


We get rid of parentheses

-A^2-14A-48=0

We add all the numbers together, and all the variables

-1A^2-14A-48=0

a = -1; b = -14; c = -48;
Δ = b2-4ac
Δ = -142-4·(-1)·(-48)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2}{2*-1}=\frac{12}{-2}
=-6
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2}{2*-1}=\frac{16}{-2}
=-8
$